Reply To: Module 3 unit 5 question about light bulb brightness

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#11074
Susan BrownSusan Brown
Keymaster

You might not have noticed it, but this explanation shows up at the quiz after you’ve submitted it:

“Remember that in a series circuit, the voltage drop across each load is proportional to the resistance of that load. In circuit A, the current must flow through the heating element and will drop some voltage across the element, leaving less voltage available to light up the light bulb. In circuit B, the light bulb gets all the voltage since the heating element is being bypassed.”

Does that make sense? You’ll get some more practice with voltage drop in Unit 8, too.